The winning Delaware Play 3 numbers for September 18, 1999 were: day 2-9-5; night 9-1-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 18, 1999 | Night | 9-1-9 | 19 | 1 |
| Sep 18, 1999 | Day | 2-9-5 | 16 | 7 |
| Sep 17, 1999 | Night | 8-2-0 | 10 | 1 |
| Sep 17, 1999 | Day | 9-3-4 | 16 | 7 |
| Sep 16, 1999 | Night | 0-7-9 | 16 | 7 |
| Sep 16, 1999 | Day | 5-5-8 | 18 | 9 |
| Sep 15, 1999 | Night | 0-9-4 | 13 | 4 |
| Sep 15, 1999 | Day | 4-6-0 | 10 | 1 |
| Sep 14, 1999 | Night | 5-1-3 | 9 | 9 |
| Sep 14, 1999 | Day | 0-7-6 | 13 | 4 |
| Sep 13, 1999 | Night | 6-4-5 | 15 | 6 |
| Sep 13, 1999 | Day | 7-0-3 | 10 | 1 |
| Sep 12, 1999 | Night | 6-5-2 | 13 | 4 |