The winning Delaware Play 3 numbers for September 5, 1999 were: night 4-1-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 5, 1999 | Night | 4-1-0 | 5 | 5 |
| Sep 4, 1999 | Night | 1-4-1 | 6 | 6 |
| Sep 4, 1999 | Day | 0-3-1 | 4 | 4 |
| Sep 3, 1999 | Night | 8-2-4 | 14 | 5 |
| Sep 3, 1999 | Day | 1-7-3 | 11 | 2 |
| Sep 2, 1999 | Night | 1-2-0 | 3 | 3 |
| Sep 2, 1999 | Day | 6-7-7 | 20 | 2 |
| Sep 1, 1999 | Night | 9-5-5 | 19 | 1 |
| Sep 1, 1999 | Day | 4-4-8 | 16 | 7 |
| Aug 31, 1999 | Night | 8-4-7 | 19 | 1 |
| Aug 31, 1999 | Day | 3-6-9 | 18 | 9 |
| Aug 30, 1999 | Night | 1-8-8 | 17 | 8 |
| Aug 30, 1999 | Day | 9-2-1 | 12 | 3 |