The winning Delaware Play 3 numbers for August 4, 1999 were: day 8-7-0; night 4-4-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 4, 1999 | Night | 4-4-7 | 15 | 6 |
| Aug 4, 1999 | Day | 8-7-0 | 15 | 6 |
| Aug 3, 1999 | Night | 2-6-0 | 8 | 8 |
| Aug 3, 1999 | Day | 0-3-4 | 7 | 7 |
| Aug 2, 1999 | Night | 1-9-3 | 13 | 4 |
| Aug 2, 1999 | Day | 5-1-6 | 12 | 3 |
| Aug 1, 1999 | Night | 1-9-7 | 17 | 8 |
| Jul 31, 1999 | Night | 7-6-2 | 15 | 6 |
| Jul 31, 1999 | Day | 5-6-3 | 14 | 5 |
| Jul 30, 1999 | Night | 7-6-5 | 18 | 9 |
| Jul 30, 1999 | Day | 6-9-8 | 23 | 5 |
| Jul 29, 1999 | Night | 0-4-7 | 11 | 2 |
| Jul 29, 1999 | Day | 6-2-6 | 14 | 5 |