The winning Delaware Play 3 numbers for July 18, 1999 were: night 0-9-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 18, 1999 | Night | 0-9-4 | 13 | 4 |
| Jul 17, 1999 | Night | 2-6-2 | 10 | 1 |
| Jul 17, 1999 | Day | 4-9-0 | 13 | 4 |
| Jul 16, 1999 | Night | 4-7-5 | 16 | 7 |
| Jul 16, 1999 | Day | 9-6-3 | 18 | 9 |
| Jul 15, 1999 | Night | 5-2-2 | 9 | 9 |
| Jul 15, 1999 | Day | 6-1-9 | 16 | 7 |
| Jul 14, 1999 | Night | 6-9-9 | 24 | 6 |
| Jul 14, 1999 | Day | 1-7-5 | 13 | 4 |
| Jul 13, 1999 | Night | 0-9-9 | 18 | 9 |
| Jul 13, 1999 | Day | 3-9-6 | 18 | 9 |
| Jul 12, 1999 | Night | 1-1-2 | 4 | 4 |
| Jul 12, 1999 | Day | 5-6-8 | 19 | 1 |