The winning Delaware Play 3 numbers for July 11, 1999 were: night 0-2-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 11, 1999 | Night | 0-2-1 | 3 | 3 |
| Jul 10, 1999 | Night | 2-2-3 | 7 | 7 |
| Jul 10, 1999 | Day | 1-6-3 | 10 | 1 |
| Jul 9, 1999 | Night | 0-8-9 | 17 | 8 |
| Jul 9, 1999 | Day | 3-9-2 | 14 | 5 |
| Jul 8, 1999 | Night | 1-0-5 | 6 | 6 |
| Jul 8, 1999 | Day | 0-5-3 | 8 | 8 |
| Jul 7, 1999 | Night | 7-5-8 | 20 | 2 |
| Jul 7, 1999 | Day | 7-3-0 | 10 | 1 |
| Jul 6, 1999 | Night | 3-2-3 | 8 | 8 |
| Jul 6, 1999 | Day | 0-9-3 | 12 | 3 |
| Jul 5, 1999 | Night | 1-5-1 | 7 | 7 |
| Jul 5, 1999 | Day | 6-4-7 | 17 | 8 |