The winning Delaware Play 3 numbers for July 4, 1999 were: night 0-5-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 4, 1999 | Night | 0-5-6 | 11 | 2 |
| Jul 3, 1999 | Night | 7-5-9 | 21 | 3 |
| Jul 3, 1999 | Day | 8-6-0 | 14 | 5 |
| Jul 2, 1999 | Night | 8-2-5 | 15 | 6 |
| Jul 2, 1999 | Day | 9-8-4 | 21 | 3 |
| Jul 1, 1999 | Night | 7-0-6 | 13 | 4 |
| Jul 1, 1999 | Day | 7-1-6 | 14 | 5 |
| Jun 30, 1999 | Night | 7-7-7 | 21 | 3 |
| Jun 30, 1999 | Day | 5-1-9 | 15 | 6 |
| Jun 29, 1999 | Night | 3-6-6 | 15 | 6 |
| Jun 29, 1999 | Day | 3-9-4 | 16 | 7 |
| Jun 28, 1999 | Night | 4-9-0 | 13 | 4 |
| Jun 28, 1999 | Day | 5-1-0 | 6 | 6 |