The winning Delaware Play 3 numbers for June 6, 1999 were: night 3-9-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jun 6, 1999 | Night | 3-9-4 | 16 | 7 |
| Jun 5, 1999 | Night | 1-7-3 | 11 | 2 |
| Jun 5, 1999 | Day | 0-1-1 | 2 | 2 |
| Jun 4, 1999 | Night | 0-5-8 | 13 | 4 |
| Jun 4, 1999 | Day | 0-4-9 | 13 | 4 |
| Jun 3, 1999 | Night | 3-1-4 | 8 | 8 |
| Jun 3, 1999 | Day | 6-9-4 | 19 | 1 |
| Jun 2, 1999 | Night | 7-8-0 | 15 | 6 |
| Jun 2, 1999 | Day | 9-9-3 | 21 | 3 |
| Jun 1, 1999 | Night | 9-3-8 | 20 | 2 |
| Jun 1, 1999 | Day | 3-8-4 | 15 | 6 |
| May 31, 1999 | Night | 8-8-6 | 22 | 4 |