The winning Delaware Play 3 numbers for December 14, 1997 were: night 4-9-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 14, 1997 | Night | 4-9-1 | 14 | 5 |
| Dec 13, 1997 | Night | 9-5-3 | 17 | 8 |
| Dec 13, 1997 | Day | 9-0-5 | 14 | 5 |
| Dec 12, 1997 | Night | 6-0-4 | 10 | 1 |
| Dec 12, 1997 | Day | 5-6-2 | 13 | 4 |
| Dec 11, 1997 | Night | 1-8-8 | 17 | 8 |
| Dec 11, 1997 | Day | 8-0-0 | 8 | 8 |
| Dec 10, 1997 | Night | 9-6-0 | 15 | 6 |
| Dec 10, 1997 | Day | 0-7-9 | 16 | 7 |
| Dec 9, 1997 | Night | 9-6-8 | 23 | 5 |
| Dec 9, 1997 | Day | 0-2-5 | 7 | 7 |
| Dec 8, 1997 | Night | 2-4-1 | 7 | 7 |
| Dec 8, 1997 | Day | 7-5-8 | 20 | 2 |