The winning Delaware Play 3 numbers for December 8, 1996 were: night 0-8-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 8, 1996 | Night | 0-8-5 | 13 | 4 |
| Dec 7, 1996 | Night | 7-1-2 | 10 | 1 |
| Dec 7, 1996 | Day | 6-8-7 | 21 | 3 |
| Dec 6, 1996 | Night | 7-4-2 | 13 | 4 |
| Dec 6, 1996 | Day | 9-6-1 | 16 | 7 |
| Dec 5, 1996 | Night | 4-4-5 | 13 | 4 |
| Dec 5, 1996 | Day | 7-8-5 | 20 | 2 |
| Dec 4, 1996 | Night | 0-5-5 | 10 | 1 |
| Dec 4, 1996 | Day | 3-0-1 | 4 | 4 |
| Dec 3, 1996 | Night | 9-7-9 | 25 | 7 |
| Dec 3, 1996 | Day | 3-0-1 | 4 | 4 |
| Dec 2, 1996 | Night | 3-2-3 | 8 | 8 |
| Dec 2, 1996 | Day | 1-0-0 | 1 | 1 |