The winning Delaware Play 3 numbers for December 1, 1996 were: night 6-3-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 1, 1996 | Night | 6-3-9 | 18 | 9 |
| Nov 30, 1996 | Night | 1-3-0 | 4 | 4 |
| Nov 30, 1996 | Day | 4-8-0 | 12 | 3 |
| Nov 29, 1996 | Night | 6-0-6 | 12 | 3 |
| Nov 29, 1996 | Day | 4-2-0 | 6 | 6 |
| Nov 28, 1996 | Night | 6-8-3 | 17 | 8 |
| Nov 28, 1996 | Day | 0-3-4 | 7 | 7 |
| Nov 27, 1996 | Night | 6-3-9 | 18 | 9 |
| Nov 27, 1996 | Day | 7-9-9 | 25 | 7 |
| Nov 26, 1996 | Night | 6-2-6 | 14 | 5 |
| Nov 26, 1996 | Day | 8-3-9 | 20 | 2 |
| Nov 25, 1996 | Night | 6-9-0 | 15 | 6 |
| Nov 25, 1996 | Day | 6-4-7 | 17 | 8 |