The winning Delaware Play 3 numbers for December 26, 1993 were: night 8-2-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 26, 1993 | Night | 8-2-4 | 14 | 5 |
| Dec 24, 1993 | Night | 0-6-9 | 15 | 6 |
| Dec 24, 1993 | Day | 9-6-3 | 18 | 9 |
| Dec 23, 1993 | Night | 0-9-5 | 14 | 5 |
| Dec 23, 1993 | Day | 9-2-3 | 14 | 5 |
| Dec 22, 1993 | Night | 4-5-0 | 9 | 9 |
| Dec 22, 1993 | Day | 0-5-7 | 12 | 3 |
| Dec 21, 1993 | Night | 3-2-4 | 9 | 9 |
| Dec 21, 1993 | Day | 6-5-5 | 16 | 7 |
| Dec 20, 1993 | Night | 5-9-2 | 16 | 7 |
| Dec 20, 1993 | Day | 5-4-9 | 18 | 9 |