The winning Delaware Play 3 numbers for December 6, 1993 were: day 5-6-4; night 7-4-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 6, 1993 | Night | 7-4-3 | 14 | 5 |
| Dec 6, 1993 | Day | 5-6-4 | 15 | 6 |
| Dec 5, 1993 | Night | 5-6-9 | 20 | 2 |
| Dec 4, 1993 | Night | 2-0-9 | 11 | 2 |
| Dec 4, 1993 | Day | 5-9-2 | 16 | 7 |
| Dec 3, 1993 | Night | 9-9-1 | 19 | 1 |
| Dec 3, 1993 | Day | 3-4-6 | 13 | 4 |
| Dec 2, 1993 | Night | 6-8-4 | 18 | 9 |
| Dec 2, 1993 | Day | 5-2-0 | 7 | 7 |
| Dec 1, 1993 | Night | 6-3-7 | 16 | 7 |
| Dec 1, 1993 | Day | 3-0-3 | 6 | 6 |
| Nov 30, 1993 | Night | 5-4-6 | 15 | 6 |
| Nov 30, 1993 | Day | 9-7-9 | 25 | 7 |