The winning Delaware Play 3 numbers for November 21, 1990 were: night 2-1-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 21, 1990 | Night | 2-1-6 | 9 | 9 |
| Nov 20, 1990 | Night | 5-2-4 | 11 | 2 |
| Nov 19, 1990 | Night | 8-8-1 | 17 | 8 |
| Nov 18, 1990 | Night | 9-1-9 | 19 | 1 |
| Nov 17, 1990 | Night | 1-8-9 | 18 | 9 |
| Nov 16, 1990 | Night | 9-1-6 | 16 | 7 |
| Nov 15, 1990 | Night | 0-0-8 | 8 | 8 |