The winning Delaware Play 3 numbers for October 3, 1990 were: night 9-0-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 3, 1990 | Night | 9-0-0 | 9 | 9 |
| Oct 2, 1990 | Night | 8-4-4 | 16 | 7 |
| Oct 1, 1990 | Night | 1-6-0 | 7 | 7 |
| Sep 29, 1990 | Night | 0-4-4 | 8 | 8 |
| Sep 28, 1990 | Night | 0-5-6 | 11 | 2 |
| Sep 27, 1990 | Night | 2-7-3 | 12 | 3 |