The winning Delaware Play 3 numbers for August 10, 1990 were: night 2-6-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 10, 1990 | Night | 2-6-0 | 8 | 8 |
| Aug 9, 1990 | Night | 2-1-5 | 8 | 8 |
| Aug 8, 1990 | Night | 8-3-9 | 20 | 2 |
| Aug 7, 1990 | Night | 6-2-5 | 13 | 4 |
| Aug 6, 1990 | Night | 7-1-4 | 12 | 3 |
| Aug 4, 1990 | Night | 0-8-0 | 8 | 8 |