The winning Delaware Play 3 numbers for November 1, 1989 were: night 2-6-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 1, 1989 | Night | 2-6-6 | 14 | 5 |
| Oct 31, 1989 | Night | 3-9-6 | 18 | 9 |
| Oct 30, 1989 | Night | 6-1-3 | 10 | 1 |
| Oct 28, 1989 | Night | 7-2-0 | 9 | 9 |
| Oct 27, 1989 | Night | 3-2-2 | 7 | 7 |
| Oct 26, 1989 | Night | 3-1-2 | 6 | 6 |