The winning Delaware Play 3 numbers for October 7, 1983 were: night 4-9-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 7, 1983 | Night | 4-9-4 | 17 | 8 |
| Oct 6, 1983 | Night | 5-6-5 | 16 | 7 |
| Oct 5, 1983 | Night | 2-0-3 | 5 | 5 |
| Oct 4, 1983 | Night | 6-8-0 | 14 | 5 |
| Oct 3, 1983 | Night | 3-5-5 | 13 | 4 |
| Oct 1, 1983 | Night | 0-6-0 | 6 | 6 |