The winning Connecticut Play4 numbers for December 28, 2019 were: day 0-5-1-9; night 6-1-9-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 28, 2019 | Night | 6-1-9-0 | 16 | 7 |
| Dec 28, 2019 | Day | 0-5-1-9 | 15 | 6 |
| Dec 27, 2019 | Night | 4-4-3-2 | 13 | 4 |
| Dec 27, 2019 | Day | 1-6-5-0 | 12 | 3 |
| Dec 26, 2019 | Night | 5-8-9-5 | 27 | 9 |
| Dec 26, 2019 | Day | 9-7-0-2 | 18 | 9 |
| Dec 25, 2019 | Night | 6-5-6-4 | 21 | 3 |
| Dec 25, 2019 | Day | 9-1-1-0 | 11 | 2 |
| Dec 24, 2019 | Night | 8-4-4-8 | 24 | 6 |
| Dec 24, 2019 | Day | 4-0-4-2 | 10 | 1 |
| Dec 23, 2019 | Night | 4-3-6-7 | 20 | 2 |
| Dec 23, 2019 | Day | 5-0-1-4 | 10 | 1 |
| Dec 22, 2019 | Night | 1-6-0-7 | 14 | 5 |
| Dec 22, 2019 | Day | 1-2-0-2 | 5 | 5 |