The winning Connecticut Play4 numbers for December 22, 2019 were: day 1-2-0-2; night 1-6-0-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 22, 2019 | Night | 1-6-0-7 | 14 | 5 |
| Dec 22, 2019 | Day | 1-2-0-2 | 5 | 5 |
| Dec 21, 2019 | Night | 2-7-6-8 | 23 | 5 |
| Dec 21, 2019 | Day | 9-0-2-4 | 15 | 6 |
| Dec 20, 2019 | Night | 5-3-6-1 | 15 | 6 |
| Dec 20, 2019 | Day | 4-6-9-9 | 28 | 1 |
| Dec 19, 2019 | Night | 0-0-8-1 | 9 | 9 |
| Dec 19, 2019 | Day | 6-1-7-7 | 21 | 3 |
| Dec 18, 2019 | Night | 1-5-7-3 | 16 | 7 |
| Dec 18, 2019 | Day | 2-3-7-2 | 14 | 5 |
| Dec 17, 2019 | Night | 0-6-6-1 | 13 | 4 |
| Dec 17, 2019 | Day | 6-7-8-1 | 22 | 4 |
| Dec 16, 2019 | Night | 1-8-0-8 | 17 | 8 |
| Dec 16, 2019 | Day | 3-2-1-7 | 13 | 4 |