The winning Connecticut Play4 numbers for December 9, 2019 were: day 8-5-4-3; night 0-3-2-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 9, 2019 | Night | 0-3-2-0 | 5 | 5 |
| Dec 9, 2019 | Day | 8-5-4-3 | 20 | 2 |
| Dec 8, 2019 | Night | 2-2-2-4 | 10 | 1 |
| Dec 8, 2019 | Day | 8-2-4-8 | 22 | 4 |
| Dec 7, 2019 | Night | 7-9-1-0 | 17 | 8 |
| Dec 7, 2019 | Day | 1-0-6-0 | 7 | 7 |
| Dec 6, 2019 | Night | 0-9-0-8 | 17 | 8 |
| Dec 6, 2019 | Day | 4-1-0-7 | 12 | 3 |
| Dec 5, 2019 | Night | 8-4-2-8 | 22 | 4 |
| Dec 5, 2019 | Day | 8-9-0-7 | 24 | 6 |
| Dec 4, 2019 | Night | 8-2-9-0 | 19 | 1 |
| Dec 4, 2019 | Day | 8-3-0-2 | 13 | 4 |
| Dec 3, 2019 | Night | 5-5-0-7 | 17 | 8 |
| Dec 3, 2019 | Day | 5-3-7-9 | 24 | 6 |