The winning Connecticut Play4 numbers for October 13, 2019 were: day 5-9-7-0; night 0-2-5-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 13, 2019 | Night | 0-2-5-0 | 7 | 7 |
| Oct 13, 2019 | Day | 5-9-7-0 | 21 | 3 |
| Oct 12, 2019 | Night | 6-3-1-9 | 19 | 1 |
| Oct 12, 2019 | Day | 3-9-4-0 | 16 | 7 |
| Oct 11, 2019 | Night | 7-9-1-7 | 24 | 6 |
| Oct 11, 2019 | Day | 8-2-5-9 | 24 | 6 |
| Oct 10, 2019 | Night | 7-2-1-5 | 15 | 6 |
| Oct 10, 2019 | Day | 9-4-8-5 | 26 | 8 |
| Oct 9, 2019 | Night | 8-0-5-0 | 13 | 4 |
| Oct 9, 2019 | Day | 8-3-5-6 | 22 | 4 |
| Oct 8, 2019 | Night | 5-8-1-4 | 18 | 9 |
| Oct 8, 2019 | Day | 4-6-3-5 | 18 | 9 |
| Oct 7, 2019 | Night | 1-7-5-6 | 19 | 1 |
| Oct 7, 2019 | Day | 5-5-0-1 | 11 | 2 |