The winning Connecticut Play4 numbers for October 7, 2019 were: day 5-5-0-1; night 1-7-5-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 7, 2019 | Night | 1-7-5-6 | 19 | 1 |
| Oct 7, 2019 | Day | 5-5-0-1 | 11 | 2 |
| Oct 6, 2019 | Night | 3-0-7-4 | 14 | 5 |
| Oct 6, 2019 | Day | 2-0-7-1 | 10 | 1 |
| Oct 5, 2019 | Night | 0-0-8-0 | 8 | 8 |
| Oct 5, 2019 | Day | 1-0-5-2 | 8 | 8 |
| Oct 4, 2019 | Night | 9-1-9-5 | 24 | 6 |
| Oct 4, 2019 | Day | 2-7-8-1 | 18 | 9 |
| Oct 3, 2019 | Night | 4-6-2-3 | 15 | 6 |
| Oct 3, 2019 | Day | 4-0-8-5 | 17 | 8 |
| Oct 2, 2019 | Night | 8-2-6-2 | 18 | 9 |
| Oct 2, 2019 | Day | 0-1-8-6 | 15 | 6 |
| Oct 1, 2019 | Night | 4-3-5-6 | 18 | 9 |
| Oct 1, 2019 | Day | 8-5-3-1 | 17 | 8 |