The winning Connecticut Play4 numbers for August 1, 2019 were: day 6-5-4-0; night 8-5-2-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 1, 2019 | Night | 8-5-2-8 | 23 | 5 |
| Aug 1, 2019 | Day | 6-5-4-0 | 15 | 6 |
| Jul 31, 2019 | Night | 8-7-4-7 | 26 | 8 |
| Jul 31, 2019 | Day | 3-8-8-9 | 28 | 1 |
| Jul 30, 2019 | Night | 6-4-5-1 | 16 | 7 |
| Jul 30, 2019 | Day | 3-8-1-5 | 17 | 8 |
| Jul 29, 2019 | Night | 2-7-7-6 | 22 | 4 |
| Jul 29, 2019 | Day | 0-8-4-0 | 12 | 3 |
| Jul 28, 2019 | Night | 9-2-0-2 | 13 | 4 |
| Jul 28, 2019 | Day | 1-5-4-5 | 15 | 6 |
| Jul 27, 2019 | Night | 3-7-2-4 | 16 | 7 |
| Jul 27, 2019 | Day | 6-5-6-5 | 22 | 4 |
| Jul 26, 2019 | Night | 2-5-8-2 | 17 | 8 |
| Jul 26, 2019 | Day | 0-8-3-0 | 11 | 2 |