The winning Connecticut Play4 numbers for March 22, 2019 were: day 1-4-1-8; night 9-7-0-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 22, 2019 | Night | 9-7-0-2 | 18 | 9 |
| Mar 22, 2019 | Day | 1-4-1-8 | 14 | 5 |
| Mar 21, 2019 | Night | 4-2-1-1 | 8 | 8 |
| Mar 21, 2019 | Day | 8-7-6-5 | 26 | 8 |
| Mar 20, 2019 | Night | 4-9-9-8 | 30 | 3 |
| Mar 20, 2019 | Day | 2-4-5-3 | 14 | 5 |
| Mar 19, 2019 | Night | 6-1-4-8 | 19 | 1 |
| Mar 19, 2019 | Day | 9-5-8-8 | 30 | 3 |
| Mar 18, 2019 | Night | 6-5-4-2 | 17 | 8 |
| Mar 18, 2019 | Day | 2-4-6-0 | 12 | 3 |
| Mar 17, 2019 | Night | 5-4-6-1 | 16 | 7 |
| Mar 17, 2019 | Day | 7-8-8-8 | 31 | 4 |
| Mar 16, 2019 | Night | 0-1-8-6 | 15 | 6 |
| Mar 16, 2019 | Day | 0-7-5-5 | 17 | 8 |