The winning Connecticut Play4 numbers for December 17, 2017 were: day 1-5-5-9; night 3-6-8-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 17, 2017 | Night | 3-6-8-7 | 24 | 6 |
| Dec 17, 2017 | Day | 1-5-5-9 | 20 | 2 |
| Dec 16, 2017 | Night | 0-2-3-8 | 13 | 4 |
| Dec 16, 2017 | Day | 9-5-3-7 | 24 | 6 |
| Dec 15, 2017 | Night | 9-5-5-1 | 20 | 2 |
| Dec 15, 2017 | Day | 9-3-5-0 | 17 | 8 |
| Dec 14, 2017 | Night | 3-1-7-3 | 14 | 5 |
| Dec 14, 2017 | Day | 7-8-7-3 | 25 | 7 |
| Dec 13, 2017 | Night | 2-5-5-5 | 17 | 8 |
| Dec 13, 2017 | Day | 2-6-4-3 | 15 | 6 |
| Dec 12, 2017 | Night | 4-6-7-2 | 19 | 1 |
| Dec 12, 2017 | Day | 6-5-3-9 | 23 | 5 |
| Dec 11, 2017 | Night | 1-9-1-1 | 12 | 3 |
| Dec 11, 2017 | Day | 0-2-5-0 | 7 | 7 |