The winning Connecticut Play4 numbers for December 3, 2013 were: day 7-1-4-7; night 9-5-0-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 3, 2013 | Night | 9-5-0-4 | 18 | 9 |
| Dec 3, 2013 | Day | 7-1-4-7 | 19 | 1 |
| Dec 2, 2013 | Night | 8-3-3-6 | 20 | 2 |
| Dec 2, 2013 | Day | 4-8-2-0 | 14 | 5 |
| Dec 1, 2013 | Night | 5-7-2-3 | 17 | 8 |
| Dec 1, 2013 | Day | 2-0-0-9 | 11 | 2 |
| Nov 30, 2013 | Night | 2-7-0-7 | 16 | 7 |
| Nov 30, 2013 | Day | 0-2-8-0 | 10 | 1 |
| Nov 29, 2013 | Night | 0-7-0-4 | 11 | 2 |
| Nov 29, 2013 | Day | 6-0-7-8 | 21 | 3 |
| Nov 28, 2013 | Night | 7-2-6-2 | 17 | 8 |
| Nov 28, 2013 | Day | 7-1-9-6 | 23 | 5 |
| Nov 27, 2013 | Night | 5-5-7-2 | 19 | 1 |
| Nov 27, 2013 | Day | 7-5-9-9 | 30 | 3 |