The winning Connecticut Play4 numbers for November 27, 2013 were: day 7-5-9-9; night 5-5-7-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 27, 2013 | Night | 5-5-7-2 | 19 | 1 |
| Nov 27, 2013 | Day | 7-5-9-9 | 30 | 3 |
| Nov 26, 2013 | Night | 9-2-9-3 | 23 | 5 |
| Nov 26, 2013 | Day | 5-8-5-6 | 24 | 6 |
| Nov 25, 2013 | Night | 8-1-2-8 | 19 | 1 |
| Nov 25, 2013 | Day | 9-9-3-4 | 25 | 7 |
| Nov 24, 2013 | Night | 7-3-8-9 | 27 | 9 |
| Nov 24, 2013 | Day | 2-5-0-3 | 10 | 1 |
| Nov 23, 2013 | Night | 9-0-3-8 | 20 | 2 |
| Nov 23, 2013 | Day | 0-2-2-1 | 5 | 5 |
| Nov 22, 2013 | Night | 4-9-8-0 | 21 | 3 |
| Nov 22, 2013 | Day | 7-1-6-8 | 22 | 4 |
| Nov 21, 2013 | Night | 0-7-1-0 | 8 | 8 |
| Nov 21, 2013 | Day | 5-2-3-5 | 15 | 6 |