The winning Connecticut Play4 numbers for October 21, 2013 were: day 2-5-8-6; night 1-7-5-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 21, 2013 | Night | 1-7-5-3 | 16 | 7 |
| Oct 21, 2013 | Day | 2-5-8-6 | 21 | 3 |
| Oct 20, 2013 | Night | 7-2-8-4 | 21 | 3 |
| Oct 20, 2013 | Day | 1-7-7-9 | 24 | 6 |
| Oct 19, 2013 | Night | 9-8-5-2 | 24 | 6 |
| Oct 19, 2013 | Day | 6-7-9-7 | 29 | 2 |
| Oct 18, 2013 | Night | 1-1-3-1 | 6 | 6 |
| Oct 18, 2013 | Day | 7-3-4-7 | 21 | 3 |
| Oct 17, 2013 | Night | 7-8-4-4 | 23 | 5 |
| Oct 17, 2013 | Day | 8-9-8-5 | 30 | 3 |
| Oct 16, 2013 | Night | 7-7-7-6 | 27 | 9 |
| Oct 16, 2013 | Day | 1-0-4-7 | 12 | 3 |
| Oct 15, 2013 | Night | 5-0-9-9 | 23 | 5 |
| Oct 15, 2013 | Day | 5-9-5-0 | 19 | 1 |