The winning Connecticut Play4 numbers for July 17, 2013 were: day 5-5-3-4; night 9-9-5-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 17, 2013 | Night | 9-9-5-8 | 31 | 4 |
| Jul 17, 2013 | Day | 5-5-3-4 | 17 | 8 |
| Jul 16, 2013 | Night | 5-9-0-3 | 17 | 8 |
| Jul 16, 2013 | Day | 8-3-6-0 | 17 | 8 |
| Jul 15, 2013 | Night | 2-2-0-3 | 7 | 7 |
| Jul 15, 2013 | Day | 3-8-6-0 | 17 | 8 |
| Jul 14, 2013 | Night | 1-1-2-5 | 9 | 9 |
| Jul 14, 2013 | Day | 4-6-1-0 | 11 | 2 |
| Jul 13, 2013 | Night | 4-1-3-4 | 12 | 3 |
| Jul 13, 2013 | Day | 5-6-9-8 | 28 | 1 |
| Jul 12, 2013 | Night | 4-3-3-3 | 13 | 4 |
| Jul 12, 2013 | Day | 5-2-8-9 | 24 | 6 |
| Jul 11, 2013 | Night | 4-1-4-9 | 18 | 9 |
| Jul 11, 2013 | Day | 9-7-4-7 | 27 | 9 |