The winning Connecticut Play4 numbers for December 3, 2012 were: day 0-9-5-0; night 9-8-6-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 3, 2012 | Night | 9-8-6-3 | 26 | 8 |
| Dec 3, 2012 | Day | 0-9-5-0 | 14 | 5 |
| Dec 2, 2012 | Night | 9-9-7-6 | 31 | 4 |
| Dec 2, 2012 | Day | 1-2-2-3 | 8 | 8 |
| Dec 1, 2012 | Night | 1-6-4-3 | 14 | 5 |
| Dec 1, 2012 | Day | 7-5-3-1 | 16 | 7 |
| Nov 30, 2012 | Night | 8-1-1-3 | 13 | 4 |
| Nov 30, 2012 | Day | 3-9-9-6 | 27 | 9 |
| Nov 29, 2012 | Night | 9-4-5-3 | 21 | 3 |
| Nov 29, 2012 | Day | 5-6-7-3 | 21 | 3 |
| Nov 28, 2012 | Night | 4-8-9-1 | 22 | 4 |
| Nov 28, 2012 | Day | 5-5-5-4 | 19 | 1 |
| Nov 27, 2012 | Night | 1-3-1-7 | 12 | 3 |
| Nov 27, 2012 | Day | 5-0-7-3 | 15 | 6 |