The winning Connecticut Play4 numbers for August 23, 2010 were: day 1-9-2-2; night 3-7-4-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 23, 2010 | Night | 3-7-4-4 | 18 | 9 |
| Aug 23, 2010 | Day | 1-9-2-2 | 14 | 5 |
| Aug 22, 2010 | Night | 1-6-4-5 | 16 | 7 |
| Aug 22, 2010 | Day | 0-0-5-9 | 14 | 5 |
| Aug 21, 2010 | Night | 0-6-5-1 | 12 | 3 |
| Aug 21, 2010 | Day | 9-9-5-6 | 29 | 2 |
| Aug 20, 2010 | Night | 0-2-8-6 | 16 | 7 |
| Aug 20, 2010 | Day | 3-6-2-5 | 16 | 7 |
| Aug 19, 2010 | Night | 7-0-7-7 | 21 | 3 |
| Aug 19, 2010 | Day | 1-7-3-5 | 16 | 7 |
| Aug 18, 2010 | Night | 8-5-4-4 | 21 | 3 |
| Aug 18, 2010 | Day | 9-3-0-3 | 15 | 6 |
| Aug 17, 2010 | Night | 1-4-3-0 | 8 | 8 |
| Aug 17, 2010 | Day | 9-1-6-6 | 22 | 4 |