The winning Connecticut Play4 numbers for December 18, 2009 were: day 4-5-5-8; night 7-8-3-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 18, 2009 | Night | 7-8-3-6 | 24 | 6 |
| Dec 18, 2009 | Day | 4-5-5-8 | 22 | 4 |
| Dec 17, 2009 | Night | 1-8-8-1 | 18 | 9 |
| Dec 17, 2009 | Day | 5-2-1-5 | 13 | 4 |
| Dec 16, 2009 | Night | 6-7-9-4 | 26 | 8 |
| Dec 16, 2009 | Day | 8-3-7-7 | 25 | 7 |
| Dec 15, 2009 | Night | 6-1-9-0 | 16 | 7 |
| Dec 15, 2009 | Day | 6-4-9-6 | 25 | 7 |
| Dec 14, 2009 | Night | 7-3-2-3 | 15 | 6 |
| Dec 14, 2009 | Day | 6-9-8-8 | 31 | 4 |
| Dec 13, 2009 | Night | 5-2-8-7 | 22 | 4 |
| Dec 13, 2009 | Day | 7-5-7-5 | 24 | 6 |
| Dec 12, 2009 | Night | 3-5-7-1 | 16 | 7 |
| Dec 12, 2009 | Day | 6-8-4-0 | 18 | 9 |