The winning Connecticut Play4 numbers for November 25, 2008 were: day 3-6-3-4; night 5-4-3-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 25, 2008 | Night | 5-4-3-0 | 12 | 3 |
| Nov 25, 2008 | Day | 3-6-3-4 | 16 | 7 |
| Nov 24, 2008 | Night | 9-5-8-0 | 22 | 4 |
| Nov 24, 2008 | Day | 1-1-8-5 | 15 | 6 |
| Nov 23, 2008 | Night | 3-4-8-9 | 24 | 6 |
| Nov 23, 2008 | Day | 3-0-4-1 | 8 | 8 |
| Nov 22, 2008 | Night | 4-1-6-0 | 11 | 2 |
| Nov 22, 2008 | Day | 3-7-6-4 | 20 | 2 |
| Nov 21, 2008 | Night | 6-8-7-3 | 24 | 6 |
| Nov 21, 2008 | Day | 7-9-7-0 | 23 | 5 |
| Nov 20, 2008 | Night | 4-2-0-9 | 15 | 6 |
| Nov 20, 2008 | Day | 6-9-4-4 | 23 | 5 |
| Nov 19, 2008 | Night | 5-9-2-5 | 21 | 3 |
| Nov 19, 2008 | Day | 5-5-4-3 | 17 | 8 |