The winning Connecticut Play4 numbers for October 2, 2008 were: day 6-1-0-5; night 5-1-3-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 2, 2008 | Night | 5-1-3-0 | 9 | 9 |
| Oct 2, 2008 | Day | 6-1-0-5 | 12 | 3 |
| Oct 1, 2008 | Night | 9-8-1-1 | 19 | 1 |
| Oct 1, 2008 | Day | 4-7-4-9 | 24 | 6 |
| Sep 30, 2008 | Night | 1-0-6-1 | 8 | 8 |
| Sep 30, 2008 | Day | 3-5-4-4 | 16 | 7 |
| Sep 29, 2008 | Night | 1-2-0-4 | 7 | 7 |
| Sep 29, 2008 | Day | 1-1-9-0 | 11 | 2 |
| Sep 28, 2008 | Night | 0-9-7-4 | 20 | 2 |
| Sep 28, 2008 | Day | 0-1-9-1 | 11 | 2 |
| Sep 27, 2008 | Night | 3-1-7-8 | 19 | 1 |
| Sep 27, 2008 | Day | 0-6-0-1 | 7 | 7 |
| Sep 26, 2008 | Night | 0-2-3-7 | 12 | 3 |
| Sep 26, 2008 | Day | 9-0-0-6 | 15 | 6 |