The winning Connecticut Play4 numbers for December 21, 2007 were: day 9-8-7-1; night 1-6-1-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 21, 2007 | Night | 1-6-1-7 | 15 | 6 |
| Dec 21, 2007 | Day | 9-8-7-1 | 25 | 7 |
| Dec 20, 2007 | Night | 9-3-7-7 | 26 | 8 |
| Dec 20, 2007 | Day | 9-2-2-5 | 18 | 9 |
| Dec 19, 2007 | Night | 8-3-1-4 | 16 | 7 |
| Dec 19, 2007 | Day | 7-8-9-1 | 25 | 7 |
| Dec 18, 2007 | Night | 3-1-2-0 | 6 | 6 |
| Dec 18, 2007 | Day | 5-7-4-1 | 17 | 8 |
| Dec 17, 2007 | Night | 7-3-7-8 | 25 | 7 |
| Dec 17, 2007 | Day | 7-9-2-5 | 23 | 5 |
| Dec 16, 2007 | Night | 2-9-4-2 | 17 | 8 |
| Dec 16, 2007 | Day | 4-3-2-3 | 12 | 3 |
| Dec 15, 2007 | Night | 4-7-4-0 | 15 | 6 |
| Dec 15, 2007 | Day | 6-8-6-0 | 20 | 2 |