The winning Connecticut Play4 numbers for December 5, 2007 were: day 0-3-1-0; night 3-5-2-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 5, 2007 | Night | 3-5-2-1 | 11 | 2 |
| Dec 5, 2007 | Day | 0-3-1-0 | 4 | 4 |
| Dec 4, 2007 | Night | 7-1-1-7 | 16 | 7 |
| Dec 4, 2007 | Day | 9-5-4-1 | 19 | 1 |
| Dec 3, 2007 | Night | 9-1-0-7 | 17 | 8 |
| Dec 3, 2007 | Day | 1-4-4-0 | 9 | 9 |
| Dec 2, 2007 | Night | 8-4-9-5 | 26 | 8 |
| Dec 2, 2007 | Day | 2-0-2-5 | 9 | 9 |
| Dec 1, 2007 | Night | 1-1-9-3 | 14 | 5 |
| Dec 1, 2007 | Day | 3-4-0-1 | 8 | 8 |
| Nov 30, 2007 | Night | 5-4-0-7 | 16 | 7 |
| Nov 30, 2007 | Day | 7-4-7-3 | 21 | 3 |
| Nov 29, 2007 | Night | 4-1-7-0 | 12 | 3 |
| Nov 29, 2007 | Day | 2-1-0-7 | 10 | 1 |