The winning Connecticut Play4 numbers for December 1, 2007 were: day 3-4-0-1; night 1-1-9-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 1, 2007 | Night | 1-1-9-3 | 14 | 5 |
| Dec 1, 2007 | Day | 3-4-0-1 | 8 | 8 |
| Nov 30, 2007 | Night | 5-4-0-7 | 16 | 7 |
| Nov 30, 2007 | Day | 7-4-7-3 | 21 | 3 |
| Nov 29, 2007 | Night | 4-1-7-0 | 12 | 3 |
| Nov 29, 2007 | Day | 2-1-0-7 | 10 | 1 |
| Nov 28, 2007 | Night | 8-1-0-5 | 14 | 5 |
| Nov 28, 2007 | Day | 0-8-1-0 | 9 | 9 |
| Nov 27, 2007 | Night | 2-8-8-8 | 26 | 8 |
| Nov 27, 2007 | Day | 3-2-2-2 | 9 | 9 |
| Nov 26, 2007 | Night | 7-9-8-5 | 29 | 2 |
| Nov 26, 2007 | Day | 2-0-0-1 | 3 | 3 |
| Nov 25, 2007 | Night | 7-9-7-9 | 32 | 5 |
| Nov 25, 2007 | Day | 8-9-2-8 | 27 | 9 |