The winning Connecticut Play4 numbers for November 25, 2007 were: day 8-9-2-8; night 7-9-7-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 25, 2007 | Night | 7-9-7-9 | 32 | 5 |
| Nov 25, 2007 | Day | 8-9-2-8 | 27 | 9 |
| Nov 24, 2007 | Night | 5-1-6-5 | 17 | 8 |
| Nov 24, 2007 | Day | 2-4-1-9 | 16 | 7 |
| Nov 23, 2007 | Night | 6-1-3-0 | 10 | 1 |
| Nov 23, 2007 | Day | 5-7-5-5 | 22 | 4 |
| Nov 22, 2007 | Night | 7-3-0-0 | 10 | 1 |
| Nov 22, 2007 | Day | 1-3-9-7 | 20 | 2 |
| Nov 21, 2007 | Night | 5-0-2-5 | 12 | 3 |
| Nov 21, 2007 | Day | 8-6-3-2 | 19 | 1 |
| Nov 20, 2007 | Night | 3-1-6-1 | 11 | 2 |
| Nov 20, 2007 | Day | 7-4-5-3 | 19 | 1 |
| Nov 19, 2007 | Night | 9-8-6-1 | 24 | 6 |
| Nov 19, 2007 | Day | 7-3-9-9 | 28 | 1 |