The winning Connecticut Play4 numbers for November 2, 2007 were: day 3-1-4-7; night 8-4-7-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 2, 2007 | Night | 8-4-7-7 | 26 | 8 |
| Nov 2, 2007 | Day | 3-1-4-7 | 15 | 6 |
| Nov 1, 2007 | Night | 8-3-5-5 | 21 | 3 |
| Nov 1, 2007 | Day | 4-2-3-6 | 15 | 6 |
| Oct 31, 2007 | Night | 2-7-9-6 | 24 | 6 |
| Oct 31, 2007 | Day | 3-9-4-2 | 18 | 9 |
| Oct 30, 2007 | Night | 6-6-3-3 | 18 | 9 |
| Oct 30, 2007 | Day | 6-9-5-1 | 21 | 3 |
| Oct 29, 2007 | Night | 2-8-7-4 | 21 | 3 |
| Oct 29, 2007 | Day | 4-4-2-5 | 15 | 6 |
| Oct 28, 2007 | Night | 9-1-0-6 | 16 | 7 |
| Oct 28, 2007 | Day | 5-6-9-1 | 21 | 3 |
| Oct 27, 2007 | Night | 7-8-5-8 | 28 | 1 |
| Oct 27, 2007 | Day | 7-9-3-0 | 19 | 1 |