The winning Connecticut Play4 numbers for October 28, 2007 were: day 5-6-9-1; night 9-1-0-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 28, 2007 | Night | 9-1-0-6 | 16 | 7 |
| Oct 28, 2007 | Day | 5-6-9-1 | 21 | 3 |
| Oct 27, 2007 | Night | 7-8-5-8 | 28 | 1 |
| Oct 27, 2007 | Day | 7-9-3-0 | 19 | 1 |
| Oct 26, 2007 | Night | 2-3-7-9 | 21 | 3 |
| Oct 26, 2007 | Day | 1-9-5-6 | 21 | 3 |
| Oct 25, 2007 | Night | 2-5-0-9 | 16 | 7 |
| Oct 25, 2007 | Day | 0-9-7-2 | 18 | 9 |
| Oct 24, 2007 | Night | 7-4-1-1 | 13 | 4 |
| Oct 24, 2007 | Day | 8-3-1-1 | 13 | 4 |
| Oct 23, 2007 | Night | 3-8-2-0 | 13 | 4 |
| Oct 23, 2007 | Day | 5-0-3-6 | 14 | 5 |
| Oct 22, 2007 | Night | 2-6-8-0 | 16 | 7 |
| Oct 22, 2007 | Day | 0-6-9-0 | 15 | 6 |