The winning Connecticut Play4 numbers for October 22, 2007 were: day 0-6-9-0; night 2-6-8-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 22, 2007 | Night | 2-6-8-0 | 16 | 7 |
| Oct 22, 2007 | Day | 0-6-9-0 | 15 | 6 |
| Oct 21, 2007 | Night | 5-8-5-1 | 19 | 1 |
| Oct 21, 2007 | Day | 6-9-6-4 | 25 | 7 |
| Oct 20, 2007 | Night | 6-6-0-7 | 19 | 1 |
| Oct 20, 2007 | Day | 5-2-7-4 | 18 | 9 |
| Oct 19, 2007 | Night | 4-0-0-9 | 13 | 4 |
| Oct 19, 2007 | Day | 7-2-5-7 | 21 | 3 |
| Oct 18, 2007 | Night | 7-4-0-8 | 19 | 1 |
| Oct 18, 2007 | Day | 4-2-9-7 | 22 | 4 |
| Oct 17, 2007 | Night | 1-0-4-3 | 8 | 8 |
| Oct 17, 2007 | Day | 2-5-1-1 | 9 | 9 |
| Oct 16, 2007 | Night | 7-2-3-4 | 16 | 7 |
| Oct 16, 2007 | Day | 2-9-8-8 | 27 | 9 |