The winning Connecticut Play4 numbers for October 17, 2007 were: day 2-5-1-1; night 1-0-4-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 17, 2007 | Night | 1-0-4-3 | 8 | 8 |
| Oct 17, 2007 | Day | 2-5-1-1 | 9 | 9 |
| Oct 16, 2007 | Night | 7-2-3-4 | 16 | 7 |
| Oct 16, 2007 | Day | 2-9-8-8 | 27 | 9 |
| Oct 15, 2007 | Night | 8-7-8-7 | 30 | 3 |
| Oct 15, 2007 | Day | 9-3-2-6 | 20 | 2 |
| Oct 14, 2007 | Night | 5-5-1-0 | 11 | 2 |
| Oct 14, 2007 | Day | 6-8-3-7 | 24 | 6 |
| Oct 13, 2007 | Night | 9-5-0-3 | 17 | 8 |
| Oct 13, 2007 | Day | 1-3-8-1 | 13 | 4 |
| Oct 12, 2007 | Night | 1-6-3-3 | 13 | 4 |
| Oct 12, 2007 | Day | 4-4-3-3 | 14 | 5 |
| Oct 11, 2007 | Night | 5-1-5-5 | 16 | 7 |
| Oct 11, 2007 | Day | 7-5-0-0 | 12 | 3 |