The winning Connecticut Play4 numbers for October 11, 2007 were: day 7-5-0-0; night 5-1-5-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 11, 2007 | Night | 5-1-5-5 | 16 | 7 |
| Oct 11, 2007 | Day | 7-5-0-0 | 12 | 3 |
| Oct 10, 2007 | Night | 5-7-3-5 | 20 | 2 |
| Oct 10, 2007 | Day | 7-6-7-6 | 26 | 8 |
| Oct 9, 2007 | Night | 2-8-9-7 | 26 | 8 |
| Oct 9, 2007 | Day | 3-9-5-6 | 23 | 5 |
| Oct 8, 2007 | Night | 1-5-2-7 | 15 | 6 |
| Oct 8, 2007 | Day | 3-3-7-0 | 13 | 4 |
| Oct 7, 2007 | Night | 0-9-1-1 | 11 | 2 |
| Oct 7, 2007 | Day | 1-5-9-7 | 22 | 4 |
| Oct 6, 2007 | Night | 0-9-1-8 | 18 | 9 |
| Oct 6, 2007 | Day | 1-9-9-2 | 21 | 3 |
| Oct 5, 2007 | Night | 9-9-0-7 | 25 | 7 |
| Oct 5, 2007 | Day | 3-0-8-0 | 11 | 2 |