The winning Connecticut Play4 numbers for October 1, 2007 were: day 6-5-1-9; night 9-1-0-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 1, 2007 | Night | 9-1-0-1 | 11 | 2 |
| Oct 1, 2007 | Day | 6-5-1-9 | 21 | 3 |
| Sep 30, 2007 | Night | 1-2-3-3 | 9 | 9 |
| Sep 30, 2007 | Day | 9-5-5-6 | 25 | 7 |
| Sep 29, 2007 | Night | 7-3-4-2 | 16 | 7 |
| Sep 29, 2007 | Day | 4-7-6-0 | 17 | 8 |
| Sep 28, 2007 | Night | 6-6-3-2 | 17 | 8 |
| Sep 28, 2007 | Day | 5-6-9-0 | 20 | 2 |
| Sep 27, 2007 | Night | 0-7-6-0 | 13 | 4 |
| Sep 27, 2007 | Day | 3-0-9-8 | 20 | 2 |
| Sep 26, 2007 | Night | 0-2-1-7 | 10 | 1 |
| Sep 26, 2007 | Day | 6-4-0-9 | 19 | 1 |
| Sep 25, 2007 | Night | 5-1-7-5 | 18 | 9 |
| Sep 25, 2007 | Day | 9-2-3-0 | 14 | 5 |