The winning Connecticut Play4 numbers for September 25, 2007 were: day 9-2-3-0; night 5-1-7-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 25, 2007 | Night | 5-1-7-5 | 18 | 9 |
| Sep 25, 2007 | Day | 9-2-3-0 | 14 | 5 |
| Sep 24, 2007 | Night | 9-0-1-7 | 17 | 8 |
| Sep 24, 2007 | Day | 1-6-8-0 | 15 | 6 |
| Sep 23, 2007 | Night | 0-9-3-7 | 19 | 1 |
| Sep 23, 2007 | Day | 1-4-6-6 | 17 | 8 |
| Sep 22, 2007 | Night | 0-1-3-3 | 7 | 7 |
| Sep 22, 2007 | Day | 4-7-3-9 | 23 | 5 |
| Sep 21, 2007 | Night | 8-8-4-1 | 21 | 3 |
| Sep 21, 2007 | Day | 5-1-5-4 | 15 | 6 |
| Sep 20, 2007 | Night | 2-2-5-6 | 15 | 6 |
| Sep 20, 2007 | Day | 8-4-9-0 | 21 | 3 |
| Sep 19, 2007 | Night | 0-9-0-8 | 17 | 8 |
| Sep 19, 2007 | Day | 3-0-1-0 | 4 | 4 |