The winning Connecticut Play4 numbers for September 19, 2007 were: day 3-0-1-0; night 0-9-0-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 19, 2007 | Night | 0-9-0-8 | 17 | 8 |
| Sep 19, 2007 | Day | 3-0-1-0 | 4 | 4 |
| Sep 18, 2007 | Night | 8-8-3-5 | 24 | 6 |
| Sep 18, 2007 | Day | 0-4-2-2 | 8 | 8 |
| Sep 17, 2007 | Night | 7-1-8-6 | 22 | 4 |
| Sep 17, 2007 | Day | 6-8-5-3 | 22 | 4 |
| Sep 16, 2007 | Night | 5-7-3-5 | 20 | 2 |
| Sep 16, 2007 | Day | 7-5-3-3 | 18 | 9 |
| Sep 15, 2007 | Night | 2-6-8-1 | 17 | 8 |
| Sep 15, 2007 | Day | 5-4-4-5 | 18 | 9 |
| Sep 14, 2007 | Night | 0-0-3-0 | 3 | 3 |
| Sep 14, 2007 | Day | 8-6-9-0 | 23 | 5 |
| Sep 13, 2007 | Night | 0-8-0-6 | 14 | 5 |
| Sep 13, 2007 | Day | 5-6-8-4 | 23 | 5 |