The winning Connecticut Play4 numbers for September 9, 2007 were: day 7-4-0-3; night 9-8-4-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 9, 2007 | Night | 9-8-4-2 | 23 | 5 |
| Sep 9, 2007 | Day | 7-4-0-3 | 14 | 5 |
| Sep 8, 2007 | Night | 5-1-4-5 | 15 | 6 |
| Sep 8, 2007 | Day | 1-6-3-9 | 19 | 1 |
| Sep 7, 2007 | Night | 5-5-9-7 | 26 | 8 |
| Sep 7, 2007 | Day | 3-8-9-6 | 26 | 8 |
| Sep 6, 2007 | Night | 5-6-2-2 | 15 | 6 |
| Sep 6, 2007 | Day | 1-3-7-9 | 20 | 2 |
| Sep 5, 2007 | Night | 2-4-7-2 | 15 | 6 |
| Sep 5, 2007 | Day | 6-2-0-7 | 15 | 6 |
| Sep 4, 2007 | Night | 7-9-7-4 | 27 | 9 |
| Sep 4, 2007 | Day | 7-1-0-8 | 16 | 7 |
| Sep 3, 2007 | Night | 3-9-4-6 | 22 | 4 |
| Sep 3, 2007 | Day | 4-2-9-5 | 20 | 2 |