The winning Connecticut Play4 numbers for September 1, 2007 were: day 5-0-4-5; night 6-2-3-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 1, 2007 | Night | 6-2-3-9 | 20 | 2 |
| Sep 1, 2007 | Day | 5-0-4-5 | 14 | 5 |
| Aug 31, 2007 | Night | 9-4-2-1 | 16 | 7 |
| Aug 31, 2007 | Day | 1-9-3-7 | 20 | 2 |
| Aug 30, 2007 | Night | 9-6-3-0 | 18 | 9 |
| Aug 30, 2007 | Day | 8-8-4-8 | 28 | 1 |
| Aug 29, 2007 | Night | 2-2-1-2 | 7 | 7 |
| Aug 29, 2007 | Day | 1-5-8-9 | 23 | 5 |
| Aug 28, 2007 | Night | 7-8-1-0 | 16 | 7 |
| Aug 28, 2007 | Day | 0-8-9-9 | 26 | 8 |
| Aug 27, 2007 | Night | 2-3-6-8 | 19 | 1 |
| Aug 27, 2007 | Day | 4-5-8-4 | 21 | 3 |
| Aug 26, 2007 | Night | 0-3-2-4 | 9 | 9 |
| Aug 26, 2007 | Day | 7-2-5-0 | 14 | 5 |