The winning Connecticut Play4 numbers for August 25, 2007 were: day 8-8-3-6; night 7-8-6-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 25, 2007 | Night | 7-8-6-2 | 23 | 5 |
| Aug 25, 2007 | Day | 8-8-3-6 | 25 | 7 |
| Aug 24, 2007 | Night | 2-3-3-2 | 10 | 1 |
| Aug 24, 2007 | Day | 9-4-7-4 | 24 | 6 |
| Aug 23, 2007 | Night | 7-9-8-3 | 27 | 9 |
| Aug 23, 2007 | Day | 8-7-2-5 | 22 | 4 |
| Aug 22, 2007 | Night | 6-7-3-5 | 21 | 3 |
| Aug 22, 2007 | Day | 4-9-1-8 | 22 | 4 |
| Aug 21, 2007 | Night | 7-1-9-4 | 21 | 3 |
| Aug 21, 2007 | Day | 0-2-6-8 | 16 | 7 |
| Aug 20, 2007 | Night | 8-4-2-3 | 17 | 8 |
| Aug 20, 2007 | Day | 4-1-6-6 | 17 | 8 |
| Aug 19, 2007 | Night | 2-7-5-6 | 20 | 2 |
| Aug 19, 2007 | Day | 0-5-4-4 | 13 | 4 |