The winning Connecticut Play4 numbers for July 18, 2007 were: day 9-8-3-5; night 6-8-7-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 18, 2007 | Night | 6-8-7-6 | 27 | 9 |
| Jul 18, 2007 | Day | 9-8-3-5 | 25 | 7 |
| Jul 17, 2007 | Night | 9-7-8-9 | 33 | 6 |
| Jul 17, 2007 | Day | 6-9-3-0 | 18 | 9 |
| Jul 16, 2007 | Night | 7-6-0-2 | 15 | 6 |
| Jul 16, 2007 | Day | 8-4-4-9 | 25 | 7 |
| Jul 15, 2007 | Night | 0-3-1-9 | 13 | 4 |
| Jul 15, 2007 | Day | 0-2-1-6 | 9 | 9 |
| Jul 14, 2007 | Night | 3-3-7-7 | 20 | 2 |
| Jul 14, 2007 | Day | 9-1-6-6 | 22 | 4 |
| Jul 13, 2007 | Night | 5-1-1-1 | 8 | 8 |
| Jul 13, 2007 | Day | 8-7-5-9 | 29 | 2 |
| Jul 12, 2007 | Night | 2-5-1-0 | 8 | 8 |
| Jul 12, 2007 | Day | 9-3-2-5 | 19 | 1 |